Finding derivatives of _, _, and _ of a function given in polar coordinates.

Practice this lesson yourself on KhanAcademy.org right now: https://www.khanacademy.org/math/ap-calculus-bc/bc-derivatives-advanced/bc-polar-functions-differentiation/e/differentiate-polar-functions?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusBC

Watch the next lesson: https://www.khanacademy.org/math/ap-calculus-bc/bc-derivatives-advanced/bc-polar-functions-differentiation/v/differentiating-polar-functions-example?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusBC

Missed the previous lesson? https://www.khanacademy.org/math/ap-calculus-bc/bc-derivatives-advanced/bc-diff-param-vec-func/v/second-derivatives-of-vector-valued-functions?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusBC

AP Calculus BC on Khan Academy: Learn AP Calculus BC – everything from AP Calculus AB plus a few extra goodies, such as Taylor series, to prepare you for the AP Test

About Khan Academy: Khan Academy is a nonprofit with a mission to provide a free, world-class education for anyone, anywhere. We believe learners of all ages should have unlimited access to free educational content they can master at their own pace. We use intelligent software, deep data analytics and intuitive user interfaces to help students and teachers around the world. Our resources cover preschool through early college education, including math, biology, chemistry, physics, economics, finance, history, grammar and more. We offer free personalized SAT test prep in partnership with the test developer, the College Board. Khan Academy has been translated into dozens of languages, and 100 million people use our platform worldwide every year. For more information, visit www.khanacademy.org, join us on Facebook or follow us on Twitter at @khanacademy. And remember, you can learn anything.

For free. For everyone. Forever. #YouCanLearnAnything

Subscribe to Khan Academy’s AP Calculus BC channel: https://www.youtube.com/channel/UC5A2DBjjUVNz8axD-90jdfQ?sub_confirmation=1

Subscribe to Khan Academy: https://www.youtube.com/subscription_center?add_user=khanacademy

You must log in to post a comment.