Calculus 2 Lecture 7.1: Integration By Parts

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Taking the cross product to calculate the surface differential in terms of the parameters Watch the next lesson: https://www.khanacademy.org/math/multivariable-calculus/surface-integrals/surface_integrals/v/surface-integral-example-part-3-the-home-stretch?utm_source=YT&utm_medium=Desc&utm_campaign=MultivariableCalculus Missed the previous lesson? https://www.khanacademy.org/math/multivariable-calculus/surface-integrals/surface_integrals/v/surface-integral-example-part-1-parameterizing-the-unit-sphere?utm_source=YT&utm_medium=Desc&utm_campaign=MultivariableCalculus Multivariable Calculus on Khan Academy: Think calculus. Then think algebra II and working with two variables in a single equation. Now generalize and combine these two mathematical concepts, and you begin…

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