3.6 .. A dog running in an open field has components of velocity vx = 2.6 m>s and vy = -1.8 m>s at t1 = 10.0 s. For the time interval from t1 = 10.0 s to t2 = 20.0 s the average acceleration of the dog has magnitude 0.45 m>s2 and direction 31.0_ measured from the +x@axis toward the +y@axis. At t2 = 20.0 s (a) what are the x- and y-components of the dog’s velocity? (b) What are the magnitude and direction of the dog’s velocity? (c) Sketch the velocity vectors at t1 and t2. How do these two vectors differ?

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Question source: “University Physics with Modern Physics by Hugh Young and Roger Freedman

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